In the above chemical reaction sequence,"A" a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The first step involves the oxidative cleavage of $1$-methylcyclohexene using ozone $(O_3)$ followed by reductive workup with $Zn / H_2O$. Th

Vedclass · Accepted Answer

$O_3, Zn / H_2O$ and $NaOH_{(aq)} / I_2$

Vedclass · Answer

(A) $1$. The first step involves the oxidative cleavage of $1$-methylcyclohexene using ozone $(O_3)$ followed by reductive workup with $Zn / H_2O$. This reaction is known as ozonolysis,which breaks the double bond to form a dicarbonyl compound ($6$-oxoheptanal). Thus,"$A$" is $O_3, Zn / H_2O$.$2$. The second step involves the reaction of the resulting ketone group with $NaOH$ and $I_2$. This is the iodoform test,which specifically reacts with methyl ketones to produce a carboxylate salt and iodoform $(CHI_3)$. Therefore,"$B$" represents the reagents for the iodoform test,which are $NaOH_{(aq)} / I_2$ (often written as $NaOH / I_2$).$3$. Comparing these with the given options,option $A$ is the correct choice.

In the above chemical reaction sequence,"$A$" and "$B$" respectively are:

Similar Questions

Identify the reagents used for the following conversion:

The reaction of $A$ to give $B$ and $C$ as shown in the reaction scheme is an example of:
$CH_2=CH_2$ $\xrightarrow[2. Zn/H_2O]{1. O_3} A$ $\xrightarrow{Conc. NaOH} B + C$
(Where $B$ is an alcohol and $C$ is a sodium salt of a carboxylic acid)

For the sequence of reactions,$A$ $\xrightarrow[{ether}]{{C_2H_5MgI}} B$ $\xrightarrow{{H_2O/H^{+}}}$ tert-Pentyl alcohol. The compound $A$ in the sequence is

Identify the name of the reaction when an aldehyde or ketone reacts with $Zn-Hg / \text{conc. } HCl$ to give an alkane.

Which of the following does not react with $NaHSO_3$ (sodium bisulphite)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module